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DUMET Medical DUMET Medical Solved Paper-2001

  • question_answer
    The standard emf of the cell\[Zn+C{{u}^{2+}}\to Cu+Z{{n}^{2+}}\] is 1.10 at \[{{25}^{o}}C\]. The emf of the cell when 0.1M \[C{{u}^{2+}}\]and 0.1 M \[Z{{n}^{2+}}\] solution are used will be:

    A)  1.10 V         

    B)  + 0.110 V

    C)  -1.10 V        

    D)  -0.11 V

    Correct Answer: A

    Solution :

    Key Idea:                  \[Zn+C{{u}^{2+}}\xrightarrow{{}}Z{{n}^{2+}}+Cu\] \[\therefore \] \[Zn\] is anode and Cu is cathode \[{{E}_{cell}}=E_{cell}^{o}-\frac{0.591}{n}\log \left[ \frac{Z{{n}^{2+}}}{C{{u}^{2+}}} \right]\] Given, \[E_{cell}^{o}=1.1\,\,V,\,n=2\] \[[Z{{n}^{2+}}]=0.1\,M,\,\,[C{{u}^{2+}}]=0.1\,M\] \[\therefore \] \[{{E}_{cell}}=1.1-\frac{0.592}{2}\log \left[ \frac{0.1}{0.1} \right]\] or \[{{E}_{cell}}=1.10-0\] \[=1.10\,V\]


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