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DUMET Medical DUMET Medical Solved Paper-2001

  • question_answer
    The standard cell potential of the galvanic cell, \[Zn/Z{{n}^{2+}}||A{{g}^{+}}/Ag\] where \[{{E}^{o}}_{Z{{n}^{2+}},Zn}=-0.76\,\,V\]and \[{{E}^{o}}_{A{{g}^{+}},Ag}=+0.80\,\,V\] is:

    A)  + 0.04V       

    B)  -0.04V

    C)  +1.54 V      

    D)  -1.54V

    Correct Answer: C

    Solution :

    Key Idea: (i) Use the formula \[E_{cell}^{o}=E_{C}^{o}-E_{A}^{o}\]. (ii) Find the cathode and anode by cell reaction and then substitute the values in terms of reduction potential. \[Zn/Z{{n}^{2+}}||\,A{{g}^{+}}/Ag\] \[\therefore \] Zn is anode and Ag is cathode. Given, \[{{E}^{o}}_{Z{{n}^{2+}}/Zn}=-0.76\,V\], \[{{E}^{o}}_{A{{g}^{+}}/Ag}=0.80\,V\] \[\therefore \] \[E_{cell}^{o}=E_{C}^{o}=E_{A}^{o}\] = 0.80 - (- 0.76) = 0.80 + 0.76 = 1.54 V


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