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DUMET Medical DUMET Medical Solved Paper-2001

  • question_answer
    If 0.15 g of a solute dissolved in 15 g of solvent is boiled at a temperature higher by\[{{0.216}^{o}}C\], than that of the pure solvent, the molecular weight of the substance is: (Molal elevation constant for the solvent is\[{{216}^{o}}C\])

    A)  10             

    B)  10.1

    C)  100           

    D)  1.01

    Correct Answer: C

    Solution :

    Key Idea: Use the following formula to find molecular formula of solute. \[M=\frac{{{K}_{b}}\times w\times 1000}{\Delta {{T}_{b}}\times W}\] where M = molecular mass of solute w = weight of solute = 0.15 g W = weight of solvent = 15 g \[\Delta {{T}_{b}}=\] elevation in boiling point \[={{0.216}^{o}}C\] \[M=\frac{2.16\times 0.15\times 100}{0.216\times 15}\] = 100


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