DUMET Medical DUMET Medical Solved Paper-2002

  • question_answer
    Two bodies are at temperatures \[{{27}^{o}}C\]and. The \[{{927}^{o}}C\] heat energy radiated by them will be in the ratio :

    A)  \[1:256\]       

    B)  \[1:64\]

    C)  \[1:4\]         

    D)  \[1:16\]

    Correct Answer: A

    Solution :

    From Stefans law of radiation \[E=\sigma \,{{T}^{4}}\] where \[\sigma \] is Stefans constant and T is absolute temperature. Given, \[{{T}_{1}}={{27}^{o}}C=273+27=300\,K\], \[{{T}_{2}}={{927}^{o}}C=273+927=1200\,K\] \[\therefore \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{(300)}^{4}}}{{{(1200)}^{4}}}=\frac{1}{256}\] Note: As the temperature is increased more and more energy is radiated.


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