A) 100 W
B) 10W
C) 1 W
D) 0. 1W
Correct Answer: D
Solution :
The rate at which electrical energy is dissipated into other forms of energy is called electric power P. \[\therefore \] \[P=\frac{E}{t}=VI\] where V is potential drop and I is current. Given, \[P=2.2\,kW=2.2\times {{10}^{3}}W\], V = 22000 volt \[\therefore \] \[I=\frac{P}{V}=\frac{2.2\times {{10}^{3}}}{22000}=\frac{22000}{22000}=\frac{1}{10}A\] From Joules heating effect of current \[\frac{H}{t}={{I}^{2}}R\] Note: Joules heating is the conversion of electrical energy into heat energy.
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