A) 15V
B) 12V
C) 9 C
D) 6 V
Correct Answer: D
Solution :
If on changing current through the coil, the back emf induced in the coil is e, then by Faradays law, we have \[e=-L\frac{di}{dt}\] where L is coefficient of self-induction, and \[\frac{di}{dt}\] is rate of change of current. Given, \[L=0.03\,H,\frac{di}{dt}=200\,A/s\] \[\therefore \] \[e=-0.03\,H,\frac{di}{dt}=200\,A/s\] \[=-6\,V\]You need to login to perform this action.
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