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DUMET Medical DUMET Medical Solved Paper-2002

  • question_answer
    Oxidation number of P in \[{{H}_{3}}P{{O}_{2}}\] is:

    A)  + 5             

    B)  + 3

    C)  + 2             

    D)  + 1

    Correct Answer: D

    Solution :

    Key Idea: The sum of oxidation states of all the elements in a neutral compound is zero. Let the oxidation state of P be \[x\] in \[{{H}_{3}}P{{O}_{2}}\] \[{{H}_{3}}P{{O}_{2}}\] \[\therefore \] \[3\times (+1)+x+(2x-2)=0\] or \[3+x-4=0\] \[\therefore \] \[x=+1\]


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