A) \[2.76\times {{10}^{12}}C/kg\]
B) \[1.76\times {{10}^{11}}C/kg\]
C) \[0.76\times {{10}^{12}}C/kg\]
D) none of these
Correct Answer: B
Solution :
Key Idea: Energy acquired due to potential difference gives the kinetic energy. Energy acquired by electron of charge e due to potential V \[E=eV\] This provides kinetic energy to the electron, i .e, \[E=eV=\frac{1}{2}m{{v}^{2}}\] where m is mass. The ratio \[\frac{e}{m}\] is given by \[\frac{e}{m}=\frac{{{v}^{2}}}{2\,V}\] Given, \[v=8.4\times {{10}^{6}}m/s,\,V=200\]volt \[\therefore \] \[\frac{e}{m}=\frac{{{(8.4\times {{10}^{6}})}^{2}}}{2\times 200}=1.76\times {{10}^{11}}C/kg\]. Note: The ratio e- is known as specific charge.
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