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DUMET Medical DUMET Medical Solved Paper-2003

  • question_answer
    The heat of 110 J is added to a gaseous system whose internal energy is 40 J, then the amount of external work done will be :

    A)  140 J         

    B)  70 J

    C)  40 J          

    D)  none of these

    Correct Answer: B

    Solution :

     Key Idea: Energy is conserved acccording to first law of thermodynamics. From first law of thermodynamics, if an amount of heat Q is given to a system, a part of it will be used in increasing the internal energy \[(\Delta U)\] of the system and rest in doing work (W) by the system. \[Q=\Delta U+W\] \[\Rightarrow \] \[-W=\Delta U-Q\] Given, \[\Delta U=40\,J,\,Q=110\,J\] \[\therefore \] \[W=-(40-110)=+70\,J\]


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