DUMET Medical DUMET Medical Solved Paper-2003

  • question_answer
    The average force necessary to stop a bullet of 20g at speed of 250 m/s, as it penetrates wood to a distance of 12 cm is:

    A)  \[2.2\times {{10}^{3}}N\]    

    B)  \[3.2\times {{10}^{3}}N\]

    C)  \[4.2\times {{10}^{3}}N\]

    D)  \[5.2\times {{10}^{3}}N\]

    Correct Answer: D

    Solution :

     Key Idea: Kinetic energy of bullet is used in doing work against resistance offered by wood. The bullet moving with velocity v and having mass m, possesses kinetic energy given by \[K=\frac{1}{2}m{{v}^{2}}\] Given, \[m=20\,g=20\times {{10}^{-3}}kg,\,v=250\,m/s\] \[K=\frac{1}{2}\times 20\times {{10}^{-3}}\times {{(250)}^{2}}\] \[K=625\,J\] This energy is used in doing work against resistance offered by wood. Also, work done = force [F] \[\times \]displacement (d) \[\therefore \] \[625=F\times 12\times {{10}^{-2}}\] \[\Rightarrow \] \[F=\frac{625}{0.12}=5.2\times {{10}^{3}}N\]


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