A) \[245\,\mu A,\,250\,\mu A\]
B) \[240\,\mu A,\,235\,\mu A\]
C) \[260\,\mu A,\,255\,\mu A\]
D) none of these
Correct Answer: A
Solution :
Key Idea: Emitter current is sum of base current and collector current. Current gain \[\beta =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{B}}}\] where \[\Delta {{i}_{C}}\] is change in collector current and \[\Delta {{i}_{B}}\] is change in base current. \[\therefore \] \[\Delta {{i}_{C}}=\beta \,\,\Delta {{i}_{B}}=49\times 5=245\,\mu A\] Also, \[\Delta {{i}_{E}}=\Delta {{i}_{B}}+\Delta {{i}_{C}}\] \[=(245+5)\mu A=250\,\mu A\]
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