A) 7.5kg
B) 15.2kg
C) 10.5kg
D) none of these
Correct Answer: A
Solution :
From kinetic theory of gases \[PV=\frac{1}{3}m{{c}^{2}}\] where P is pressure, V is volume, m is mass and c is velocity. \[\therefore \] \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}\] \[\Rightarrow \] \[{{m}_{2}}=\frac{{{P}_{2}}}{{{P}_{1}}}{{m}_{1}}\] Given, \[{{P}_{1}}={{10}^{7}}N/{{m}^{2}},{{P}_{2}}=2.5\times {{10}^{6}}N/{{m}^{2}}\], \[{{m}_{1}}=10\,kg\]. \[\therefore \] \[{{m}_{2}}=\frac{2.5\times {{10}^{6}}}{{{10}^{7}}}\times 10=2.5\,kg\] Quantity of gas taken out \[=10-2.5=7.5\,kg\].
You need to login to perform this action.
You will be redirected in
3 sec
