A) \[6.6\,\overset{o}{\mathop{A}}\,\]
B) \[1.2\,\overset{o}{\mathop{A}}\,\]
C) \[0.133\,\overset{o}{\mathop{A}}\,\]
D) \[0.4\,\overset{o}{\mathop{A}}\,\]
Correct Answer: D
Solution :
For an accelerating voltage V, the maximum X-ray photon energy is given by \[h{{v}_{\max }}=eV\] The minimum wavelength corresponding to this maximum energy is \[{{\lambda }_{\min }}=\frac{hc}{eV}\] where h is Plancks constant and c is speed of light. \[\therefore \]\[{{\lambda }_{\min }}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 30\times {{10}^{3}}}=0.4\,\overset{o}{\mathop{A}}\,\]
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