A)
B)
C)
D) None of these
Correct Answer: C
Solution :
In the given question in option (c), \[3\,\Omega \]. and \[6\,\Omega \]resistances are in parallel, hence equivalent resistance is \[\frac{1}{R}=\frac{1}{6}+\frac{1}{3}=\frac{9}{18}\] \[\Rightarrow \] \[R=2\,\Omega \] The two \[2\,\Omega \]. resistances are now connected in series, hence equivalent resistance is \[R=2\,\Omega +2\,\Omega =4\,\Omega \] Note: The value of the equivalent resistance of the resistances connected in parallel is less than the value of the smallest resistance among those resistances.You need to login to perform this action.
You will be redirected in
3 sec