A) \[48\,\,\Omega \]
B) \[24\,\,\Omega \]
C) \[56\,\,\Omega \]
D) \[36\,\,\Omega \]
Correct Answer: A
Solution :
Key Idea: Potential difference across shunt and galvanometer resistance is same. Let G be resistance of galvanometer and \[{{i}_{g}}\] the current through it. Since, G and S are in parallel, we have Ammeter \[{{i}_{g}}\times G=(i-{{i}_{g}})\times S\] \[\Rightarrow \] \[\frac{{{i}_{g}}}{i}=\frac{S}{S+G}\] \[\therefore \] \[\frac{10}{50}=\frac{12}{12+G}\] \[\Rightarrow \] \[12+G=60\] \[\Rightarrow \] \[G=48\,\Omega \]You need to login to perform this action.
You will be redirected in
3 sec