question_answer

\[C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}\xrightarrow{PB{{r}_{3}}}\] \[\xrightarrow{{{H}_{2}}O}D\] Here, D is:

A)  \[C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,H-O-C{{H}_{2}}-C{{H}_{3}}\]

B)  \[C{{H}_{3}}-O-\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}C{{H}_{3}}\]

C)  \[C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}C{{H}_{2}}OH\]

D)  \[C{{H}_{3}}-C{{H}_{2}}\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{-C}}\,H-C{{H}_{2}}OH\]

Correct Answer: C

Solution :

\[C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}\xrightarrow{PB{{r}_{3}}}C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  \underset{(A)}{\mathop{Br}}\, \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}\] \[\xrightarrow{Mg}C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  \underset{(B)}{\mathop{MgBr}}\, \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}\]     iso-pentylalcohol or 3-methyl butane-2-ol