A) \[{{C}_{3}}{{H}_{5}}{{O}_{3}}\]
B) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
C) \[{{C}_{3}}{{H}_{10}}{{O}_{5}}\]
D) \[{{C}_{3}}{{H}_{4}}{{O}_{3}}\]
Correct Answer: B
Solution :
Given: moles of carbohydrate = 0.833 Hydrogen = 10 g \[\because \] 0.833 moles of carbohydrate has hydrogen = 10 g \[\therefore \] 1 mole of carbohydrate has hydrogen \[=\frac{10}{0.833}\times 1\] = 12 g Given: empirical formula of carbohydrate \[=C{{H}_{2}}O\] \[\because \] \[C{{H}_{2}}O\] contains hydrogen = 2 g hydrogen per mole Molecular formula should contain hydrogen \[=\frac{12}{2}\times 2=12\] \[\therefore \] Molecular formula of hydro carbon\[={{C}_{6}}{{H}_{12}}{{O}_{6}}\]
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