DUMET Medical DUMET Medical Solved Paper-2003

  • question_answer
    \[{{P}_{4}}+3NaOH+3{{H}_{2}}O\xrightarrow{{}}A+3Na{{H}_{2}}P{{O}_{2}}\]here, A is:

    A)  \[N{{H}_{3}}\]        

    B)  \[P{{H}_{3}}\]

    C)  \[{{H}_{3}}P{{O}_{4}}\]

    D)  \[{{H}_{3}}P{{O}_{3}}\]

    Correct Answer: B

    Solution :

    \[{{P}_{4}}+3NaOH+3{{H}_{2}}O\to P{{H}_{3}}+3Na{{H}_{2}}P{{O}_{2}}\] \[\therefore \] [A] is phosphene \[{{(P{{H}_{3}})}^{(A)}}\] This reaction is the laboratory method of preparation of phosphine gas. During this reaction, phosphorus disproportionate into phosphine and sodium hydrogen phosphite.


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