A) nearer the \[N{{H}_{3}}\] end
B) at the centre
C) nearer \[HCl\] end
D) anywhere
Correct Answer: C
Solution :
Key Idea: According to Grahams law of diffusion \[r\propto \sqrt{\frac{1}{M}}\] Mol. wt. of \[HCl=1.35.5=36.5\] Mol. wt. of \[N{{H}_{3}}=14+3=17\] \[\because \] Rate of diffusion is faster for \[N{{H}_{3}}\] \[\therefore \] Product \[N{{H}_{4}}Cl\] will be formed near \[HCl\]end.You need to login to perform this action.
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