DUMET Medical DUMET Medical Solved Paper-2003

  • question_answer
    \[Zn(s)+C{{l}_{2}}(1\,atm)\xrightarrow{{}}Z{{n}^{2+}}2C{{l}^{-}}\] \[{{E}^{o}}_{cell}\] of the cell is 2.12 V. To increase E:

    A)  \[[Z{{n}^{2+}}]\] should be increased

    B)  \[[Z{{n}^{2+}}]\] should be decreased

    C)  \[[C{{l}^{-}}]\] should be decreased

    D)  \[{{P}_{C{{l}_{2}}}}\] should be decreased

    Correct Answer: A

    Solution :

    According to Nernsts equation. \[{{E}_{cell}}={{E}^{o}}_{cell}-\frac{nRT}{F}\log \frac{{{C}_{1}}}{{{C}_{2}}}\] where, \[{{C}_{1}}=\] concentration of anode \[=[Z{{n}^{2+}}]\] \[{{C}_{2}}=\] concentration of cathode \[=[C{{l}^{-}}]\] \[\therefore \] EMF of cell to be maximum \[{{C}_{1}}\]or \[[Z{{n}^{2+}}]\] should be increased.


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