A) geometrical isomerism
B) optical isomerism
C) both [a] and [b]
D) none of the above
Correct Answer: B
Solution :
Key Idea: (i) A compound shows geometrical isomerism if it has at least one carbon-carbon double bond and the two groups attached to the same carbon atom are different. (ii) A compound shows optical isomerism if it has at least one asymmetric or chiral carbon atom and does not have plane of symmetry. \[H-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,}}\,*-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-OH\] \[\because \] The compound has one asymmetric carbon (marked *) atom. \[\therefore \] It shows optical isomerism. \[\because \] The compound does not have C = C. \[\therefore \] It does not show geometrical isomerism.
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