A) \[C{{O}_{3}}^{2-}\]
B) \[S{{O}_{3}}^{2-}\]
C) \[{{S}^{2-}}\]
D) \[S{{O}_{4}}^{2-}\]
Correct Answer: A
Solution :
Key Idea: During carbonate ion test compounds having \[CO_{3}^{2-}\] ions decompose on heating to give \[C{{O}_{2}}\] gas. The presence of \[C{{O}_{2}}\]gas is detected by effervesces it produces. \[\because \] Salts having \[S{{O}_{3}}^{2-},{{S}^{2-}}\] and \[S{{O}_{4}}^{2-}\] ions form comparatively stronger acids (than\[{{H}_{2}}C{{O}_{3}}\]). \[\therefore \] They evolve \[C{{O}_{2}}\] and give effervescence when heated with \[N{{a}_{2}}C{{O}_{3}}\] solution. \[\because \] Salts having \[CO_{3}^{2-}\] ions do not react with\[N{{a}_{2}}C{{O}_{3}}\]. \[\therefore \] \[N{{a}_{2}}C{{O}_{3}}\] cannot be used to identify \[CO_{3}^{2-}\].
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