A) Crystal system - Cubic Axial Distance - \[a\ne b=c\] Axial angles - \[\alpha =\beta \ne \gamma \] Examples - Cu, KCl
B) Crystal system - Monoclinic Axial Distance - \[\alpha \ne b=c\]Axial angles - \[\alpha \ne \beta =\gamma \]\[={{90}^{o}}\]Examples - \[pbCr{{O}_{2}}\],\[pbCr{{O}_{4}}\]
C) Crystal system - Rhombohedral Axial Distance - a = b = c Axial angles - \[\alpha =\beta =\gamma \]\[\ne {{90}^{o}}\] Examples - \[CaC{{O}_{3}}\],Hgs
D) Crystal system - Triclinic Axial Distance - a = b = c Axial angles - \[\alpha \ne \beta =\gamma \]\[\ne {{90}^{o}}\] Examples - \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]\[CuS{{O}_{4}}5{{H}_{2}}O\]
Correct Answer: C
Solution :
[a] For cubic \[a=b=c\] and \[a=\beta =\gamma ={{90}^{o}}\] So, it is wrong. [b] For monoclinic \[a\ne b\ne c\] and \[\alpha =\gamma ={{90}^{o}}\]and \[\beta \ne {{90}^{o}}\] \[\therefore \] is wrong. [c] For triclinic \[a\ne b\ne c\] and \[\alpha \ne \beta \ne \gamma \ne {{90}^{o}}\] \[\therefore \] It is wrong. [d] For rhombohedral crystal system \[a=b=c\]and \[\alpha =\beta =\gamma \ne {{90}^{o}}\].You need to login to perform this action.
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