A) ethylene bromohydrin
B) 1, 2-dibromo ethane
C) ethanol
D) none of the above
Correct Answer: A
Solution :
\[{{H}_{2}}C=C{{H}_{2}}\xrightarrow{B{{r}_{2}}/{{H}_{2}}O}\underset{(A)}{\mathop{\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}}}\,\] \[\therefore \] Compound A is ethylene bromohydrin. It is an addition reaction.You need to login to perform this action.
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