A) \[n\,\,\,G\]
B) \[(n-1)\,\,G\]
C) \[\frac{G}{n}\]
D) \[\frac{G}{n-1}\]
Correct Answer: B
Solution :
Let G is resistance of galvanometer and \[{{i}_{g}}\] the current through it. From Ohms law \[{{i}_{g}}=\frac{V}{G+R}\] \[\Rightarrow \] \[G+R=\frac{V}{{{i}_{g}}}\] \[\Rightarrow \] \[R=\frac{V}{{{i}_{g}}}-G\] Given, \[V=n\,\,V,{{i}_{g}}=\frac{V}{G}\] \[\therefore \] \[R=\frac{n\,\,V}{V/G}-G=n\,G-G=(n-1)\,G\]You need to login to perform this action.
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