A) 0.2T
B) 0.8 T
C) 0.1 T
D) 1.6 T
Correct Answer: A
Solution :
Magnetic field [b] due to current carrying wire at a distance r is \[B=\frac{{{\mu }_{0}}}{2\,\pi }\frac{i}{r}\] \[\Rightarrow \] \[\frac{{{B}_{1}}}{{{B}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] \[\Rightarrow \] \[{{B}_{2}}=\frac{{{r}_{1}}}{{{r}_{2}}}{{B}_{1}}\] Given, \[{{r}_{1}}={{r}_{2}},\,\,{{r}_{2}}=2r,\,\,{{B}_{1}}=0.4\,T\] \[\therefore \] \[{{B}_{2}}=\frac{r}{2\,r}\times 0.4=0.2\,T\]You need to login to perform this action.
You will be redirected in
3 sec