A) MO
B) \[{{M}_{2}}{{O}_{3}}\]
C) \[{{M}_{2}}O\]
D) \[{{M}_{2}}{{O}_{5}}\]
Correct Answer: C
Solution :
Key Idea: First find equivalent weight, then molecular weight and then molecular formula by using various formulas. Equivalent weight of metal \[=\frac{weight\text{ }of\text{ }metal}{weight\text{ }of\text{ }oxygen}\times 8\] Given, weight of oxide of metal = 3.6 g Weight of metal = 3.2 g Vapour density of metal = 32 \[\therefore \] Equivalent weight of metal \[=\frac{3.2}{3.6-3.2}\times 8\] \[=\frac{3.2}{0.4}\times 8\] = 64 Molecular weight \[=2\times \] vapour density \[=2\times 32\] = 64 \[n=\frac{molecular\text{ }weight}{equivalent\text{ }weight}\] \[=\frac{64}{64}=1\] Let the formula of metal oxide \[={{M}_{2}}{{O}_{n}}\] \[\therefore \] Formula of metal oxide \[={{M}_{2}}O\,(\because \,n=1)\]
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