A) \[N{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}>Sb{{H}_{3}}\]
B) \[Sb{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}>N{{H}_{3}}\]
C) \[Sb{{H}_{3}}>N{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}\]
D) \[N{{H}_{3}}>P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}\]
Correct Answer: C
Solution :
Compounds \[N{{H}_{3}}\,\,\,\,P{{H}_{3}}\,\,\,\,As{{H}_{3}}\,\,\,\,Sb{{H}_{3}}\] Boiling point (in K) 238 185 211 254 (i) From \[P{{H}_{3}}\] to \[Sb{{H}_{3}}\] boiling point increases regularly due to increase in van der Waals forces of attraction. (ii) \[N{{H}_{3}}\] has exceptionally high boiling point due to hydrogen bonding. \[\therefore \] The boiling points are of the order \[Sb{{H}_{3}}>N{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}\]
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