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DUMET Medical DUMET Medical Solved Paper-2004

  • question_answer
    Sulphur-35 (34.96903 amu) emits a \[\beta \] particle but no \[\gamma \]-rays, the product is chlorine-35 (34.96885 amu). The maximum energy emitted by the \[\beta \]-particle is :

    A)  0.016767 MeV

    B)  1.6758 MeV

    C)  0.016758 MeV

    D)  16.758 MeV

    Correct Answer: A

    Solution :

    Key Idea: The maximum energy emitted by \[\beta \]-particles is equal to binding energy. Binding/energy = mass defect \[\times 931.5\,MeV\] Given, mass of sulphur = 34.96903 amu Mass of chlorine = 34.96885 amu Mass defect = mass of sulphur - mass of chlorine = 34.96903 - 34.96885 = 0.00018 amu \[\therefore \] Binding energy = mass defect \[\times 931.5\,MeV\] or \[=0.00018\times 931.5\,MeV\] = 0.16767 MeV


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