A) \[{{n}_{4}}\to {{n}_{1}}\]
B) \[{{n}_{2}}\to {{n}_{1}}\]
C) \[{{n}_{4}}\to {{n}_{2}}\]
D) \[{{n}_{3}}\to {{n}_{1}}\]
Correct Answer: A
Solution :
Key Idea: \[E=\frac{hc}{\lambda }\] or \[E=\frac{1}{\lambda }\] \[\therefore \] Decrease in wavelength, increases the energy. \[\therefore \] Energy difference in \[{{n}_{4}}\to {{n}_{1}}\] transition is maximum. \[\therefore {{n}_{4}}\to {{n}_{1}}\]transition has minimum wavelength.
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