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DUMET Medical DUMET Medical Solved Paper-2005

  • question_answer
    \[N{{H}_{4}}COON{{H}_{2}}(s)2N{{H}_{3}}(g)+C{{O}_{2}}(g)\]   if equilibrium pressure is 3 aim for the above reaction. \[{{K}_{p}}\] for the reaction is:

    A)  4             

    B)  27

    C)  4/27          

    D)  1/27

    Correct Answer: B

    Solution :

    Key Idea: Use law of mass action to find \[{{k}_{p}}\]for the reaction. \[N{{H}_{4}}COON{{H}_{2}}(s)2N{{H}_{3}}(g)+C{{O}_{2}}(g)\] \[\therefore \] \[{{K}_{P}}=\frac{p_{N{{H}_{3}}}^{2}\times {{p}_{C{{O}_{2}}}}}{{{p}_{N{{H}_{4}}COON{{H}_{2}}(s)}}}\] But \[{{p}_{N{{H}_{4}}COON{{H}_{2}}(s)}}=1\] (\[\because \] P of solids is taken as one) \[\therefore \] \[{{K}_{p}}={{p}^{2}}_{N{{H}_{3}}}\times {{p}_{C{{O}_{2}}}}\] \[={{(3)}^{2}}\times 3\] = 27


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