A) 3100
B) 3200
C) 3600
D) 4200
Correct Answer: C
Solution :
Latent heat is defined as the heat which flows to or from a material without a change to temperature, and specific heat is amount of heat per unit mass required to raise the temperature by one degree Celsius. Hence, total heat required = heat required to convert ice into water at \[{{0}^{o}}C\,\,({{Q}_{1}})+\] heat required to increase the temperature of water upto \[{{100}^{o}}C\,({{Q}_{2}})+\] heat required to convert water into steam at \[{{100}^{o}}C\,({{Q}_{3}})\]. \[\therefore \] \[{{Q}_{1}}=mL=5\times 80=400\,cal\] \[{{Q}_{2}}=ms\,\Delta t=5\times 1\times (100-0)=500\,cal\] \[{{Q}_{3}}=mL=5\times 540=2700\,cal\] \[\therefore \] \[Q={{Q}_{1}}+{{Q}_{2}}+{{Q}_{3}}=400+500+2700\] = 3600 cal.
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