A) 1 : 2
B) 1 : 3
C) 2 : 3
D) 4 : 1
Correct Answer: A
Solution :
\[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\] give three ions, \[{{[Co{{(N{{H}_{3}})}_{5}}Cl]}^{2+}},2C{{l}^{-}}\], i.e., 1 : 2You need to login to perform this action.
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