A) 1.24
B) 1.36
C) 1.66
D) 1.76
Correct Answer: B
Solution :
\[{{A}_{2}}\] 11% get dissociated, i.e., 11 in 100. \[{{A}_{2}}\,\,\,\,\,\,\,\,\,\,\,\,\rightleftarrows \,\,\,\,\,\,\,\,\,B+C\] 100 0 0 initial 100-11 11 11 at equilibrium = 89 \[{{K}_{c}}=\frac{[BC][C]}{[{{A}_{2}}]}=\frac{11\times 11}{89}\] \[=1.359\approx 1.36\]You need to login to perform this action.
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