A) 17.35 MeV
B) 18.06 MeV
C) 177.35 MeV
D) 170.35 MeV
Correct Answer: A
Solution :
Key Idea: The total energy released in reaction (Q) is equal to the difference in kinetic energy of the final particles and of initial particles. The total mass of the initial particles \[{{m}_{1}}1.007825+7.016004\] \[=8.023829\,\,u\] and the total mass of final particles \[{{m}_{f}}=2\times 4.002603\] \[=8.005206\,\,u\] Difference between initial and final mass of particles \[\Delta m={{m}_{i}}-{{m}_{f}}=8.023829-8.005206\] \[=0.018623\,\,u\] The Q-value is given by \[Q=(\Delta m)\,{{c}^{2}}\] \[=0.018623\times 93.15\] \[=17.35\,\,MeV\]You need to login to perform this action.
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