A) 2, 0, 0, + 1/2
B) 2, 1, -1, +1/2
C) 3, 1, -1, \[\pm \] 1/2
D) 3, 0, 0, \[\pm \] ½
Correct Answer: C
Solution :
\[_{17}Cl=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{5}}\] Hence, 15th electron in chlorine atom is unpaired. From the above, it is clear that for this electron, \[n=3\] \[l=1\] \[m=-1\] \[s=\pm \frac{1}{2}\]You need to login to perform this action.
You will be redirected in
3 sec