A) 50%
B) 72.24%
C) 55.3%
D) 43%
Correct Answer: B
Solution :
Per cent ionic character \[=16\,({{x}_{A}}\sim {{x}_{B}})+3.5\,{{({{x}_{A}}\sim {{x}_{B}})}^{2}}\] \[=16\,(4.0-1.2)+3.5\,{{(4.0-1.2)}^{2}}\] \[=44.8+27.44\] \[=72.24%\]You need to login to perform this action.
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