A) bond order three and iso-electronic
B) bond order three and weak-field ligands
C) bond order two and \[\pi \]-acceptor
D) iso-electronic and weak-field ligands
Correct Answer: A
Solution :
Species | Structure | Bond order | No. of electrons |
\[C{{N}^{-}}\] | \[C\equiv N\] | 3 | 6 + 7 + 1 = 14 |
CO | \[C\overset{\leftarrow }{\mathop{=}}\,O\] | 3 | 6 + 8 = 14 |
\[N{{O}^{+}}\] | \[N\equiv {{O}^{+}}\] | 3 | 7 + 8 - 1 = 14 |
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