A) 2.78 N
B) 2.56 N
C) 2.82 N
D) 2.71 N
Correct Answer: C
Solution :
Let the tension in each section AB and AC be T. Now, from the condition of equilibrium it is clear that the horizontal components are equal in magnitude and opposite to each other so they cancel out each other. Hence, \[mg=2T\,\,\sin \,{{10}^{o}}\] \[\therefore \] \[T=\left[ \frac{mg}{2\sin {{10}^{o}}} \right]=\frac{0.1\times 9.8}{2\times 0.1736}=2.82\,N\]You need to login to perform this action.
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