A) \[10\,\,\Omega \]
B) \[1\,\,\Omega \]
C) \[0.1\,\,\Omega \]
D) \[0.01\,\,\Omega \]
Correct Answer: C
Solution :
Let shunt resistance be S. Voltage across shunt is Now, \[V=(I-{{I}_{g}}).\,\,S\] and \[{{I}_{g}}\,.\,{{R}_{G}}=(I-{{I}_{g}})\,.\,\,S\] \[\Rightarrow \] \[S=\frac{{{I}_{g}}{{R}_{G}}}{(I-{{I}_{g}})}\] \[=\frac{{{10}^{-3}}\times 10}{(100\times {{10}^{-3}}-1\times {{10}^{-3}})}\] \[=\frac{10}{99}=0.1\,\Omega \]You need to login to perform this action.
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