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DUMET Medical DUMET Medical Solved Paper-2009

  • question_answer
    The motion of a particle executing SHM in one dimension is described by \[x=-0.5\,\,\,\sin \,(2t+\pi /4),\] where \[x\] is in metre and t in second. The frequency of oscillation in Hz is

    A)  \[2\]           

    B)  \[\pi \]

    C)  \[\pi /2\]             

    D)  \[1/\pi \]

    Correct Answer: D

    Solution :

     Given, equation of SHM \[x=-0.5\,\sin \,(2t+\pi /4)\] Now, comparing with general equation of SHM, we get \[x=A\,\sin \,(\omega \,t+\phi )\] we get \[\omega =2\] or \[2\pi f=2\] or \[f=\frac{1}{\pi }Hz\]


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