A) \[NO_{3}^{-}\]
B) \[C{{l}^{-}}\]
C) \[SO_{4}^{2-}\]
D) \[C{{H}_{3}}CO{{O}^{-}}\]
Correct Answer: D
Solution :
Acid of \[NO_{3}^{-}=HN{{O}_{3}}\] Acid of \[C{{l}^{-}}=HCl\] Acid of \[SOP_{4}^{2-}={{H}_{2}}S{{O}_{4}}\] Acid of \[C{{H}_{3}}CO{{O}^{-}}=C{{H}_{3}}COOH\] Since, conjugate acid of \[C{{H}_{3}}CO{{O}^{-}}\]is weakest, it is the strongest conjugate base.
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