A) 1.0 kcal \[mo{{l}^{-1}}\]
B) 2.0 kcal \[mo{{l}^{-1}}\]
C) 18.55 kcal \[mo{{l}^{-1}}\]
D) 11.7 kcal \[mo{{l}^{-1}}\]
Correct Answer: B
Solution :
\[\Delta H=\Delta {{H}_{dissociation}}+\Delta {{H}_{neutalisation}}\] \[\therefore \,\,\,\Delta {{H}_{diss}}=\Delta H-\Delta {{H}_{neut}}=-2\times 13.7-(-25.4)\] \[=-27.5+25.4=-2.0\,\,kcal\,\,mo{{l}^{-1}}\]You need to login to perform this action.
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