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DUMET Medical DUMET Medical Solved Paper-2009

  • question_answer
    The values of electronegativity of atoms A and are 1.2 and 4.0 respectively. The per cent ionic character of the A - B bond is

    A)  50%            

    B)  72.24%

    C)  55.3%          

    D)  43%

    Correct Answer: B

    Solution :

    Per cent ionic character \[=16\,({{x}_{A}}\sim {{x}_{B}})+3.5\,{{({{x}_{A}}\sim {{x}_{B}})}^{2}}\] \[=16\,(4.0-1.2)+3.5\,{{(4.0-1.2)}^{2}}\] \[=44.8+27.44\] \[=72.24%\]


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