A) \[{{[Co{{F}_{4}}]}^{2-}}\]
B) \[{{[Co{{(NHS)}_{4}}]}^{2-}}\]
C) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
D) \[{{[CoC{{l}_{4}}]}^{2-}}\]
Correct Answer: C
Solution :
\[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\] Shows octahedral crystal field. According to crystal field theory, octahedral crystal field show higher CFSE. Therefore, \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\] shows the highest CFSE among the given complex ions.
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