A) By heating \[AlC{{l}_{3}}\,\,6{{H}_{2}}O\]
B) By passing dry \[HCl\] gas on heated aluminium powder
C) By passing dry chlorine gas on heated aluminium powder
D) By passing dry chlorine gas over a heated mixture of alumina and coke
Correct Answer: A
Solution :
[a] \[2AlC{{l}_{3}}6{{H}_{2}}O\xrightarrow{\Delta }A{{l}_{2}}{{O}_{3}}+6HCl\uparrow \] \[+9{{H}_{2}}O\uparrow \] [b] \[2Al+\underset{(dry)}{\mathop{3HCl}}\,\xrightarrow{{}}2AlC{{l}_{3}}+3{{H}_{2}}\uparrow \] [c] \[2Al+\underset{(dry)}{\mathop{3C{{l}_{2}}}}\,\xrightarrow{{}}2AlC{{l}_{3}}\] [d] \[A{{l}_{2}}{{O}_{3}}+3C+3C{{l}_{2}}\xrightarrow{{}}2AlC{{l}_{3}}+3CO\uparrow \]
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