A) \[S{{O}_{2}}+2{{H}_{2}}S\xrightarrow{{}}2{{H}_{2}}O+3S\]
B) \[2Na+{{O}_{2}}\xrightarrow{{}}N{{a}_{2}}{{O}_{2}}\]
C) \[N{{a}_{2}}O+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}{{O}_{2}}\]
D) \[4KCl{{O}_{3}}\xrightarrow{{}}3KCl{{O}_{4}}+KCl\]
Correct Answer: C
Solution :
[a] \[\overset{+4}{\mathop{S}}\,{{O}_{2}}+2{{H}_{2}}\overset{2-}{\mathop{S}}\,\xrightarrow{{}}2{{H}_{2}}O+3\overset{0}{\mathop{S}}\,\] [b] \[2\overset{0}{\mathop{N}}\,a+{{O}_{2}}\xrightarrow{{}}{{\overset{+1}{\mathop{Na}}\,}_{2}}{{O}_{2}}\] [c]\[{{\overset{+1}{\mathop{Na}}\,}_{2}}\overset{-1}{\mathop{O}}\,+{{\overset{+1-2}{\mathop{{{H}_{2}}SO}}\,}_{4}}\xrightarrow{{}}{{\overset{+1}{\mathop{Na}}\,}_{2}}\overset{-2}{\mathop{S}}\,{{O}_{4}}+\overset{+1}{\mathop{{{H}_{2}}}}\,\overset{-1}{\mathop{{{O}_{2}}}}\,\] [d] \[\overset{+5}{\mathop{4KCl{{O}_{3}}}}\,\xrightarrow{{}}\overset{+7}{\mathop{3KCl{{O}_{4}}}}\,+KCl\] Therefore, only in Eq. [c], there is no change in valency.
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