A) 4870 Pa
B) 4.87 Pa
C) 0.00487 Pa
D) 0.33 Pa
Correct Answer: B
Solution :
Osmotic pressure, \[\pi =CRT\] \[=\frac{0.0020}{1000}\,(mol{{m}^{-3}})\times \frac{8.314}{101.266}\] \[(L\,\,atm\,{{K}^{-1}}mo{{l}^{-1}})\times 293\,K\] \[=4.87\times {{10}^{-3}}atm\] = 4.87 PaYou need to login to perform this action.
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