A) a visible light
B) an infrared wave
C) a microwave
D) a radio wave
Correct Answer: C
Solution :
We have, \[{{B}_{y}}=2\times {{10}^{-7}}\sin (0.5\times {{10}^{3}}x+1.5\times {{10}^{11}}t)\] Comparing with the standard equation, we get \[{{B}_{y}}={{B}_{0}}\sin \,(kx+\omega \,t)\] \[k=0.5\times {{10}^{3}}\] \[\Rightarrow \] \[\lambda =\frac{2\pi }{0.5\times {{10}^{3}}}=0.01256\] The wavelength range of microwaves is \[{{10}^{-3}}\] to 0.3. The wavelength of this wave lies between \[{{10}^{-3}}\] to 0.3, so the equation represents a microwaves.
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