A) \[8.4\times {{10}^{-5}}\]
B) \[7.1\times {{10}^{-9}}\]
C) \[4.2\times {{10}^{-10}}\]
D) \[1.7\times {{10}^{-19}}\]
Correct Answer: A
Solution :
Free energy and equilibrium constant are related as, \[\Delta \,G=-2.303\,\,RT\,\log \,K\] \[78\times {{10}^{3}}=-2.303\times 8.314\times 1000\times \log \,\,K\] \[\log K=-\frac{78}{2.303\times 8.314}\] \[=-4.073\] K = antilog \[(-4.0.73)\] \[=8.43\times {{10}^{-5}}\]You need to login to perform this action.
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